Convert Megaelectronvolt to Foot-pound
1 megaelectronvolt = 1.1817e-13 foot-pound (ft·lbf). For example, 10 megaelectronvolt = 1.1817e-12 foot-pound and 100 megaelectronvolt = 1.1817e-11 foot-pound. Type any value below to convert megaelectronvolt to foot-pound both ways — it runs entirely in your browser.
Torque vs energy: Foot-pound (ft·lbf) is used both as a unit of ENERGY — where 1 N·m = 1 joule exactly — and as a unit of TORQUE (a twisting force × distance). This page converts the ENERGY meaning, so the figures above are correct for work and heat. A newton-metre of torque is a different physical quantity and does NOT convert into joules, kilowatt-hours or calories.
Megaelectronvolt to Foot-pound conversion formula
To convert megaelectronvolt to foot-pound, multiply by 1.1817e-13:
foot-pound = megaelectronvolt × 1.1817e-13
Going the other way, 1 foot-pound = 8.4624e+12 megaelectronvolt, so
megaelectronvolt = foot-pound × 8.4624e+12.
Megaelectronvolt to Foot-pound — worked examples
| Megaelectronvolt | Foot-pound |
|---|---|
| 1 MeV | 1.1817e-13 ft·lbf |
| 2 MeV | 2.3634e-13 ft·lbf |
| 3 MeV | 3.5451e-13 ft·lbf |
| 5 MeV | 5.9085e-13 ft·lbf |
| 10 MeV | 1.1817e-12 ft·lbf |
| 25 MeV | 2.9543e-12 ft·lbf |
| 50 MeV | 5.9085e-12 ft·lbf |
| 100 MeV | 1.1817e-11 ft·lbf |
Megaelectronvolt ↔ Foot-pound reference table
| Megaelectronvolt → Foot-pound | Foot-pound → Megaelectronvolt |
|---|---|
| 1 MeV = 1.1817e-13 ft·lbf | 1 ft·lbf = 8.4624e+12 MeV |
| 2 MeV = 2.3634e-13 ft·lbf | 2 ft·lbf = 1.6925e+13 MeV |
| 5 MeV = 5.9085e-13 ft·lbf | 5 ft·lbf = 4.2312e+13 MeV |
| 10 MeV = 1.1817e-12 ft·lbf | 10 ft·lbf = 8.4624e+13 MeV |
| 20 MeV = 2.3634e-12 ft·lbf | 20 ft·lbf = 1.6925e+14 MeV |
| 50 MeV = 5.9085e-12 ft·lbf | 50 ft·lbf = 4.2312e+14 MeV |
| 100 MeV = 1.1817e-11 ft·lbf | 100 ft·lbf = 8.4624e+14 MeV |
| 250 MeV = 2.9543e-11 ft·lbf | 250 ft·lbf = 2.1156e+15 MeV |
| 500 MeV = 5.9085e-11 ft·lbf | 500 ft·lbf = 4.2312e+15 MeV |
| 1000 MeV = 1.1817e-10 ft·lbf | 1000 ft·lbf = 8.4624e+15 MeV |
About megaelectronvolt and foot-pound
Megaelectronvolt: A megaelectronvolt is the energy an electron gains across a one-million-volt potential — 1 MeV = 1.602176634 × 10⁻¹³ J (the elementary charge is exact since the 2019 SI redefinition). Standard in nuclear and particle physics.
Foot-pound: A foot-pound is the energy of one pound-force acting over one foot — about 1.3558 joules. The same number (as the pound-foot, lbf·ft) is also the common US unit of TORQUE.
Frequently asked questions
- How many foot-pound are in 1 megaelectronvolt?
- 1 megaelectronvolt = 1.1817e-13 foot-pound (ft·lbf).
- How do I convert megaelectronvolt to foot-pound?
- Multiply the number of megaelectronvolt by 1.1817e-13. For example, 10 megaelectronvolt = 10 × 1.1817e-13 = 1.1817e-12 foot-pound.
- How many megaelectronvolt are in 1 foot-pound?
- 1 foot-pound = 8.4624e+12 megaelectronvolt.
- Which is bigger, megaelectronvolt or foot-pound?
- 1 foot-pound equals 8.4624e+12 megaelectronvolt, so a foot-pound is the larger unit.